The first constraint tells us that's what y is So negative 5x plus 8 is equal to negative 2 Now, we have one equation with one unknown We can just solve for x We have 10x plus So we can multiply it We can distribute this 2 onto both of these terms So we have 2 times negative 5x is negative 10x And then 2 times 8 is 161) is a critical point The second derivative test f xx = 2;f yy = 2;f xy = 0 shows this a local minimum withY is the set of even numbers X \Y is the set of all even numbers in the interval ( 2;4), ie X \Y = f0;2g X Y = fx 2R j 2 < x < 4 or x = 2k for some k 2Zg (f) Let A be the xzplane in R3 and B be the yzplane in R3 Use set comprehension notation to describe the sets A\B and AB Answer A = 8 < 2 4 x y z 3 5 2R3
Buad 306 Chapter 3 Forecasting Everyday Forecasting Weather